APTITUDE REPEATED QUESTIONS WITH ANSWERS

REPEATED QUESTIONS ON GEOMETRY WITH ANSWERS 1. A conical tent is to accommodate 10 persons.  Each person must have 6 sq.meter space to sit and 30 cubic meters of air to breathe.  What will be the height of the cone? a. 150m b. 37.5 m c. 15 m d. 75 m Answer: c Explanation: Each person needs 6 sq meters of space. So πr2=6×10=60 Total volume of the tent = 30 × 10 = 300 So 1/3(πr2)h=300 ⇒ 1/3×60×h=300 h = 15 m 2. The length, breadth, and height of a room are in the ratio 3:2:1. If the breadth and height are halved, while the length is doubled. Then the total area of the 4 walls of the room will be decreased by a. 30% b. 18.75% c. 15% d. 13.6% Answer:a Explaination: Given l:b:h=3:2:1 let h=10, b = 20, and l = 30 area = 2(l+b)h area= 2*(3x+2x)*x = 2(30+20)10=1000 Now after those adjustments in the measurements, l=60, b=10, h=5 area= 2(l+b)h = 2(60+10)5=700 Percentage decrease= (1000−700)/1000 ×1000 =30 % 3. Arun makes a popular brand of ice cream in a rectangular-shap...

REPEATED REASONING QUESTIONS WITH ANSWERS 1. In 4 years, Raj’s father age twice as raj, Two years ago, Raj’s mother’s age twice as raj. If Raj is 32yrs old in eight yrs from now, what is the age of Raj’s mother and father? a.42,44 b.41,40 c.52,46 d.40,45 Answer.c Explaination: Raj present age = 32 – 8 = 24. After 4 years Raj’s age is 28. and Raj’s father's age is 28 x 2 = 56, and his present age is 52. Two years ago, Raj’s age is 22. and his mother’s age is 22 x 2 = 44. His mother’s present age = 46 2.   In a series of numbers, the next number is formed by adding 1 to the sum of the previous numbers, and the 10th number is 1280.  Then what is the first number in the series? (series will be like this x , x+1, (x+(x+1))+1,……) a. 1 b. 4 c. 5 d. None of these Answer: Option B Explanation. The given series is x, x + 1, 2x + 2, 4x + 4 …… If you observe the pattern here,  the coefficient of x + 1 is in the powers of 2. So 4th term has a power of 2, 5th term h...

REPEATED QUESTIONS ON EQUATIONS WITH ANSWERS 1.For real number x, int(x) denotes integer part of x.int(x) is the largest integer less than or equal to x.int(1,2)=1,int(-2,4)=-3.  Find the value of int(1/2)+int(1/2+ 100)+int(1/2+2/100)+….+int(1/2+99/100) a.100 b.120 c.130 d.150 Answer:d Explaination: int (1/2) = 0 int (1/2 + 100 ) = 100 into (1/2 + 2/100) = 0 …… int ( 1/2 + 50/100 ) = 1 int (1/2 + 51 /100) = 1 ……. int (1/2 + 99/100) = 1 So 100 +  1 + 1 + …..50 times = 150 2.There are 100 wine glasses.  I offered my servant to 3 paise for every broken glass to be delivered safely and forfeit 9 paisa for every glass broken at the end of day. He recieved Rs.2.40 .how many glass did he break. a.20 b.73 c.5 d.8 Answer:c Explaination:If a glass has been broken, he has to loose 3 paisa + 9 paise = 12 paise Assume K  glasses got broken 100 x 3 – 12 x K = 240 ⇒K=5 3.If f(f(n))+f(n)=2n+3 and f(0)=1, what is the value of f(2...

REPEATED QUESTIONS ON TIME, SPEED, DISTANCE WITH SOLUTIONS 1. Joke is faster than Paul, Joke, and Paul each walk 24 KM. The sum of their speed is 7 Km per hour. And the sum of the times taken by them is 14 hours. Then, Joke speed is a. 3 KM/Hr b. 4 KM/Hr c. 5 KM/Hr d.7 KM/Hr Answer: a Explanation :Speed = Distance/Time let the speed of joke x then speed of paul will be 7-x 24/x + 24/(7−)x =14 Try to plug in the values from the options. If Joke speed is 4 the paul is 3. 2. George while driving along the highway saw road markers that are at equal distances from each other. He crosses the markers every 20 seconds. If he increases his speed by x meters per second, he crosses the markers at every 15 seconds. But if he increases his speed by y meters per second, he crosses the marker at every 10th second. If y-x = 40 meters per second, then what is the distance between two markers. Answer:1200 Explanation: Let speed be =z m/s then Distance= 20z m (z+x)15=20z; (z+y)10=20z Also given that y – ...

REPEATED QUESTIONS ON SERIES AND PROGRESSIONS WITH ANSWERS 1.How many odd and even numbers are there between 42 and 400?? Find the sum of odd numbers and the sum of even numbers! a.39338 b.33214 c.45321 d.12321 Answer: a Explanation: Odd numbers are from 43 to 399. Number of odd numbers = (l−a)/d+1= 399−43/2+1=179 Their sum =n/2(l+a)= 39559 Even numbers are from 44 to 398. Number of even numbers =(l−a)/d+1=(398−44)/2+1=178 Their sum =178/2(398+44)=39338 2. In a staircase, there are 10 steps. A child is attempting to climb the staircase. Each time she can either make 1 step or 2 steps. In how many different ways can she climb the staircase? a.10 b.21 c.36 d.None of these Answer: d Explanation: Use Fibonacci series, with starting two terms as 1, 2. So next terms are 3, 5, 8, 13, 21, 34, 55, 89 3. Find the average of the terms in the series 1-2+3-4+5….+199-200 a.-0.1 b.-0.2 c.-0.5 d.-0.3 Answer:c Explaination:(1-2) +(3-4) + (5-6) +……..(199-200) = -100 Average = 100 / 200 = -0.5 4.A series...

REPEATED QUESTIONS ON WORK AND TIME WITH ANSWERS 1. George and Mark can paint 720 boxes in 20 days, Mark and Harry in 24 days and Harry and George in 15 days. George works for 4 days, Mark for 8 days and Harry for 8 days.  The total number of boxes painted by them is a. 252 b. 516 c. 348 d. 492 Answer:  c Explanation: Capacities of these people as followes G + M = 720/20 = 36 M + H = 720/24 = 30 H + G = 720/15 = 48 Adding all above we get 2(G + M + H ) = 114 ⇒ G + M + H = 114/2 = 57 Now individual capacities are given below G = 27 ; M = 9; H = 21 So 27 × 4 + 9 × 8 + 21 × 8 = 348 2. 4 men can check exam papers in 8 days working 5 hours regularly. What is the total hours when 2 men will check the double of the papers in 20 days? a.7 hrs b.8 hrs c.10 hrs d.5 hrs Answer:b Explanation: Let a man can do 1 unit of work in 1 hour. Total units of work = 4 x 8 x 5 = 160 units. Now work = 2 x 160 = 320 units. Now 2 men work for 20 days. Let in...

REPEATED QUESTIONS ON RATIO, PROPORTION AND AVERAGES WITH ANSWERS 1. The average temperature of Tuesday Wednesday and Thursday was 37 C. The average temperature of Wednesday and Thursday and Friday was 38 C. if the temperature on Friday was 39 C. Find the temperature on Tuesday. a. 37.33 b. 38.33 c. 36 d. None of the above Answer:c Explanation: (Tues + Wed + Thurs)/3=37 Tues + Wed + Thurs=111…(1) (Wed + Thurs + Fri)/3=38 (Wed + Thurs + Fri) =114…(2) Given Friday is 39. Then, (2) – (1) Fri – Tues = 3 So 39 – Tues = 3 Tuesday =36 2. There are 5 boxes in a cargo. The weight of the 1st box is 200 KG, the weight of the 2nd box is 20% higher than the third box, whose weight is 25% higher than the 1st box weight. The 4th box which weighs 350 KG is 30% lighter than the 5th box. Find the difference in the average weight of the 4 heaviest boxes and the four lightest boxes. a.45 b.24 c.53 d.75 Answer:d Explanation: weight of 1st box=200 weight of 3rd box=(125/100)*200=250 weight of 2nd box=(120/1...

REPEATED ALLEGATIONS AND MIXTURES QUESTIONS WITH SOLUTIONS 1. Apples cost L rupees per kilogram for the first 30 kilograms and Q per kilogram for each additional kilogram.  If the price paid for 33 kilograms of Apples is Rs.1167 and for 36 kilograms of apples if Rs.1284, then the cost of the first 10 kgs of apples is: a. Rs.117 b. Rs.350 c. Rs.281 d. Rs.1053 Answer: b Explanation: Given that 30L + 3Q = 1167 30L + 6Q = 1284 Solving we get Q =  39, L = 35 So cost of first 10 kgs of apples = 35 × 10 = 350 2. A mixture of 150 liters of wine and water contains 20% water. How much more water should be added so that water becomes 25% of the new mixture? A. 7 liters B. 15 liters C. 10 liters D. 9 liters Answer: Option C Explanation: Number of liters of water in150 liters of the mixture = 20% of 150 = 20/100 * 150 = 30 liters. P liters of water added to the mixture to make water 25% of the new mixture. The total amount of water becomes (30 + P) and the total volume of the mixture is (1...

REPEATED PERCENTAGE QUESTIONS WITH SOLUTIONS 1. In paper A, one student got 18 out of 70, and in paper B he got 14 out of 30. In which paper he did farewell? a.45.3 b.46.6 c.34.8 d.44.3 Answer: b Explanation. Find the percentages. Paper A = 18/70 x 100 = 25.7 Paper B = 14/30 x 100 = 46.6 2. Rajesh calculated his average over the last 24 tests and found it to be 76. He finds out that the marks for three tests have been inverted by mistake. The correct marks for these tests are 87, 79, and 98. What is the approximate percentage difference between his actual average and his incorrect average? a.0 b.1 c.14 d.22 Answer: a Explanation:Incorrect value is: 78, 97, 89 correct values are: 87, 79, 98 difference between correct and incorrect value is= 9 + 9 -18=0 3. In a certain city, 60% of the registered voters are congress supporters and the rest are BJP supporters. In an assembly election, if 75% of the registered congress supporters and 20% of the registered BJP supporters are expected to vot...